4x^2+9x=28

Solution for 4x^2+9x=28 equation:

4x^2+9x=28

We move all terms to the left:

4x^2+9x-(28)=0

a = 4; b = 9; c = -28;
Δ = b2-4ac
Δ = 92-4·4·(-28)
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{529}=23$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-23}{2*4}=\frac{-32}{8}
=-4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+23}{2*4}=\frac{14}{8}
=1+3/4
$